A train travelling at uniform speed passes by a platform 220m long in 30s and another platform 325m long in 39 sec.Find the length of the train and the speed of the train
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Here goes the solution!
Given, s = t + 220/30 _______( i )
and , s = t + 325/38 _______( ii )
Solving ( i ) & ( ii ), we get,
39(t + 220) = 30(t + 325)
39t + 8580 = 30t + 9750
9t = 1170
t = 130 m
Put in ( i ), we get
Speed = 130 + 220/30
= 350/30
= 11.66 m/sec
S = 3600 × 11.66/1000
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