Question

A train travelling from a railway station and moving with uniform accelaration attains a speed of 90 km/hr (convert) in 10 mins find the accelaration?

Answer 1

ANSWER:

The train has a acceleration of 0.041 m/s²

GIVEN:

v = 90 kmph

t = 10 minutes

u = 0

CONVERSIONS:

1 kmph = 5/18 m/s

90 kmph = 90 × 5/18

90 kmph = 5 × 5 = 25m/s

1 min = 60 seconds

10 min = 10× 60 s

10 min = 600 s

TO FIND:

a= ?

FORMULAE:

v = u + at

EXPLAINATION:

25 = 0 + a × 600

a = 25/600

a = 0.25/6

a = 0.041 m/s²

The train has a acceleration of 0.041 m/s².

Answer 2

Answer:

Given:

initial velocity = 0

final velocity = 90km/hr = 90 x 5/18 = 25 m/s

time = 10 mins = 10 x 60 = 600 sec

Solution:

v = u + at

a = (v - u) /t

a = (25 - 0) /600

a = 25/600 = 1/24 = 0.04166667 m/s^2