a train travelling with a speed of 36 kilometre per hour is brought to rest by applying brakes if it travels a distance of 100 M under uniform retardation before coming to rest find a value of the retardation
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Answered by
4
u=36km/h =10m/sec
v=0
s=100m
a=?
2as=v^2-u^2
2×a×100=-100
a=-1/2
a=-0.5m/sec And (minus sign indicates retardation)
v=0
s=100m
a=?
2as=v^2-u^2
2×a×100=-100
a=-1/2
a=-0.5m/sec And (minus sign indicates retardation)
Answered by
1
v= distance/time and v= 36 km/h = 10m/s
so,
v^2=u^2+2as
0=10^2+2a×100
100/100=2a
a=0.5m/s^2
so,
v^2=u^2+2as
0=10^2+2a×100
100/100=2a
a=0.5m/s^2
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