A train travelling with a speed of 36km/h is brought be rest applying brakes. If it travels a distance of 100m under uniform retardation before coming to rest,find the value of retardation?
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initial velocity is 36×1000/60×60=10m/s
final velocity is 0
distance=s=100m
by applying formula we get
v^2=u^2+2as
(0)^2=(10)^2+2×(-a)×100
0=100+200×(-a)
200×a=100
a=100/200
a=0.5m/s^2
final velocity is 0
distance=s=100m
by applying formula we get
v^2=u^2+2as
(0)^2=(10)^2+2×(-a)×100
0=100+200×(-a)
200×a=100
a=100/200
a=0.5m/s^2
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Answer:
first you can see the initial velocity
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