Question

A train travels 16.8 kilometre in 25 minutes. find the speed of the train in
1) km/h
2)m/s​

Answer 1

Given

• Distance travelled = 16.8 km
• Time taken = 25 min

Find out

• Speed of train

1. in km/h
2. in m/s

Solution

★ In first condition

➟ Time = 25min

★ 1 hours = 60 minutes ★

➟ Time = 25/60

➟ t = 5/12 h

As we know that

➟ speed = Distance/time

➟ speed = 16.8/5/12

➟ speed = 16.8 × 12/5

➟ speed = 40.32 km/h

Hence, speed of train is 40.32 km/h

$\rule{200}3$

★ In second condition

• Distance = 16.8km

★ 1km = 1000m ★

➟ 16.8 × 1000

➟ 16800m

• Time = 25 min

★ 1 minutes = 60 seconds ★

➟ 25 × 60

➟ 1500 sec

➟ speed = Distance/time

➟ speed = 16800/1500

➟ speed = 168/15

➟ speed = 11.2 m/s

Hence, speed of train 11.2 m/s

$\rule{200}3$

Answer 2

${ \huge{ \bold{ \underline{ \underline{ \purple{Question:-}}}}}}$

A train travels 16.8 kilometre in 25 minutes. find the speed of the train in : -

1) km/h

2)m/s

${ \huge{ \bold{ \underline{ \underline{ \blue{Answer:-}}}}}}$

✒Given : -

• Distance = 16.8 km
• Time Taken = 35 min.

✒To Find : -

• Speed of train in km/h and in m/s..

★ In First Case : -

$\dashrightarrow\sf{Time=25m}$

$\dashrightarrow\sf{\cancel\dfrac{25}{60}}$

$\dashrightarrow\sf{\dfrac{5}{12}}$

✒Formula Used :

$\leadsto\sf{{ \large{ \bold{ \bold{ \bold{ \orange{Speed=\dfrac{Distance}{Time}}}}}}}}$

✒On Calculating : -

$\dashrightarrow\sf{Speed=\dfrac{16.8}{\dfrac{5}{12}}}$

$\dashrightarrow\sf{Speed=16.8\times\dfrac{12}{5}}$

$\leadsto\sf{{ \small{ \boxed{ \bold{ \bold{ \red{Speed=40.32km/h}}}}}}}$

Therefore, Speed of train is 40.32 km/h

★ In Second Case : -

$\dashrightarrow\sf\bold{Distance=16.8km}$

$\dashrightarrow\sf{16.8\times{1000}}$

$\dashrightarrow\sf{16800m}$

$\dashrightarrow\sf\bold{Time=25m}$

$\dashrightarrow\sf{25\times{60}}$

$\dashrightarrow\sf{1500\:seconds}$

✒Formula Used : -

$\leadsto\sf{{ \large{ \bold{ \bold{ \bold{ \orange{Speed=\dfrac{Distance}{Time}}}}}}}}$

✒On Calculating : -

$\dashrightarrow\sf{Speed=\cancel\dfrac{16800}{1500}}$

$\leadsto\sf{{ \small{ \boxed{ \bold{ \bold{ \purple{Speed=11.2m/s}}}}}}}$

Therefore, Speed of train is 11.2 m/s