A train travels 180 km at a uniform speed if the speed had been 6 km per hour more it would have taken 1 hour less for the same journey find the speed of the train
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Heya Mate....................
Here is your answer..........................
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Let the speed of train be x.
Distance = 180km
so, time = 180/x
when speed is 6 km/h more, time taken = 180/x+6
According to question:
180 / x-180 / x+6 = 1
180 (x+6-x) / x(x+6) = 1
180*6 = x(x+6)
1080 = x^2 + 6x
x^2 + 6x - 1080
x^2 + 36x - 30x - 1080
x(x + 36) -30(x + 36)
(x - 30)(x + 36) = 0
x = 30, -36
But x being speed cannot be negative.
So, x = 30
Hence, the speed of the train is 30km/h.
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Thanks..............................
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