Question

A train travels 180 km at a uniform speed if the speed has been 9 km per hour more it would have taken 1 hour less for the same journey find the speed of the train​

Answer 1

Hii its tom85

let the speed of train be X

time taken by train = 180/X

time taken by train when it's

speed

9km/hr more =180/(9 + X)

according to question

180/x - 180/(9+X )= 1

1620 + 180x - 180x = 9x +x^2

x^2 + 9x - 1620 = 0

x^2 + 45x - 36x - 1620=0

(x + 45)(x-36)=0

x=36 and -45

speed of train is 36km/hr

______/\______☺️

hope it may helps you

Answer 2

Given,
Distance=180

Let
SPEED OF TRAIN=x

Then,
TIME TAKEN=180/x

180/x - 180/x+9 = 1

180x + 162 -180x / x^2 + 9x = 1

X^2 + 9x - 162=0
Splitting the middle term,

(x+18)(x-9)=0

x=-18 x=9

x=9 because speed can’t be -ve