A train travels 200 Km at a speed of 80 Km/hr. How fast should it travel on its return so that the avg speed is 100 Km/hr??
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Answer:
133 km ph approximately
Explanation:
As we know that
=> total distance / total time taken = average speed
now given
distance = 400 km (200+200 for return)
average speed = 100 kmph
now let us consider that total time taken is X hours so
400/X= 100
it gives 4 hours it means 4 hours taken to cover 400 km but 200 km we had already covered with a speed of 80 kmph
i.e 200/80= 2.5
it means out of 4 hours 2.5 hours spent
now remaining time is for remaining trip
=> = 200/4-2.5
=> 200/1.5 = 133 kmph aprox
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