À train travels 20km at à uniform speed of 60km h-1 and the next 20km at à uniform speed of 80km h-¹. calculate its average speed.
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hiii
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here in first case
distance travelled(d1)=20 km
speed of the train(s1)=60 km/h
time(t1)=?
then t1= d1
s1
t1=20
60
t1=1/3
Now in second case
distance travelled(d2)=20 km
speed of the train(s2)=80 km/h
time(t2)=?
then t2= d2
s2
= t2=20
80
= t2=1/4
Now average speed= total distance
total time
=> d1+d2
s1+s2
= 20+20
1/3+1/4
on solving this
= 480
7
= 68.57 km/h
____________________________________________________________
if helpful mark as brainliest and dont forget to hit the red hearty box
_______________________________________________________________
here in first case
distance travelled(d1)=20 km
speed of the train(s1)=60 km/h
time(t1)=?
then t1= d1
s1
t1=20
60
t1=1/3
Now in second case
distance travelled(d2)=20 km
speed of the train(s2)=80 km/h
time(t2)=?
then t2= d2
s2
= t2=20
80
= t2=1/4
Now average speed= total distance
total time
=> d1+d2
s1+s2
= 20+20
1/3+1/4
on solving this
= 480
7
= 68.57 km/h
____________________________________________________________
if helpful mark as brainliest and dont forget to hit the red hearty box
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2
À train travels 20km at à uniform speed of 60km h-1 and the next 20km at à uniform speed of 80km h-¹. calculate its average speed.
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