A train travels 20km at a uniform speed of 60km/-h and the next 20 km at a uniform speed of 80 km/-h. Calculate its average speed.
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d1=20km
s1=60km/h
t1=d1/s1=20/60=1/3
d2=20km
s2=80km/h
t2=d2/s2=20/80=1/4
average speed = (d1+d2)/(t1+t2)
= 40/(3/4)
= 160/3=36.66km/h
s1=60km/h
t1=d1/s1=20/60=1/3
d2=20km
s2=80km/h
t2=d2/s2=20/80=1/4
average speed = (d1+d2)/(t1+t2)
= 40/(3/4)
= 160/3=36.66km/h
jassijassar:
But the answer is 68.57Km/-1h.
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