Question

A train travels 25 km/h faster than a bus. The time required to travel 1500 km by the train is 3 hours less than the time required by the bus. Find the speed of the train. Distance (km) → Speed (km/h) → Time (h).

Answer 1

Answer:

speed of bus =x

train =x+25

time taken to travel 1500km by bus=t

train=t-3

x=1500/t

x+25=1500/t-3

equate both terms and solve

you get answer

Answer 2

Answer:

speed of train = 125km/h, time= 12 hours, distance = 1500 km

Step-by-step explanation:

let the speed of train = x km/h

=> speed of bus = x-25 km/h

since time = distance/speed

=> [1500/(x-25)] -(1500/x)= 3

=> [ 1500x- (x-25) ( 1500) = 3x(x-25)

=> 37500 = 3x²-75x

=> 3x²-75x-37500 =0

=> x²-25x - 12500 = 0

=> x²+100x-125x-12500= 0

=> x(x+100) -125( x+100) = 0

=> (x+100) ( x-125) = 0

=> x-125 = 0

=> x = 125km/h

time taken to reach 1500 km by the train

= 1500/125 = 12 hours

speed of train = 125km/h

distance covered = 1500 km

time taken= 12 hours