A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train. (write some data and type the answe
Answers
Solution :-
→ Distance to cover = 360km.
→ Let Speed of Train = S km/h .
Than,
→ Time_1 = (Distance/Speed)
→ Time_1 = (360/S) hours.
Now,
→ Distance to cover = 360km.
→ Speed of Train = (S+5) km/h .
Than,
→ Time_2 = (Distance/Speed)
→ Time_2 = 360/(S+5) hours.
Given That,
→ Time_1 - Time_2 = 1 hour.
So,
→ 360/S - 360/(S + 5) = 1
→ 360(S + 5) - 360S / S(S + 5) = 1
→ 360S + 1800 - 360S = S² + 5S
→ S² + 5S - 1800 = 0
→ S² + 45S - 40S - 1800 = 0
→ S(S + 45) - 40(S + 45) = 0
→ (S + 45)(S - 40) = 0
→ S = (-45) & 40 km/h.
{ Speed in -ve ≠ } .
Hence, The Speed of Train is 40km/h.
Answer:
speed = 40km/hr
Step-by-step explanation:
Consider the given question,
Distance =360 km
Speed =x km/hr
When speed is increase (x+5) km/hr
Given expression is written as,
⇒
x
360
−
(x+5)
360
=1
⇒
x(x+5)
x+5−x
=
360
1
⇒x
2
+5x=1800
⇒x
2
+5x−1800=0
⇒x
2
+45x−40x−1800=0
⇒x(x+45)−40(x+45)=0
⇒(x+45)(x−40)=0
⇒x=40,−45
But, speed can not be negative.
Hence, speed is 40 km/hr
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