Question

A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train. (write some data and type the answe​

Answer 1

Solution :-

→ Distance to cover = 360km.

→ Let Speed of Train = S km/h .

Than,

→ Time_1 = (Distance/Speed)

→ Time_1 = (360/S) hours.

Now,

→ Distance to cover = 360km.

→ Speed of Train = (S+5) km/h .

Than,

→ Time_2 = (Distance/Speed)

→ Time_2 = 360/(S+5) hours.

Given That,

→ Time_1 - Time_2 = 1 hour.

So,

→ 360/S - 360/(S + 5) = 1

→ 360(S + 5) - 360S / S(S + 5) = 1

→ 360S + 1800 - 360S = S² + 5S

→ S² + 5S - 1800 = 0

→ S² + 45S - 40S - 1800 = 0

→ S(S + 45) - 40(S + 45) = 0

→ (S + 45)(S - 40) = 0

→ S = (-45) & 40 km/h.

{ Speed in -ve ≠ } .

Hence, The Speed of Train is 40km/h.

Answer 2

Answer:

speed = 40km/hr

Step-by-step explanation:

Consider the given question,

Distance =360 km

Speed =x km/hr

When speed is increase (x+5) km/hr

Given expression is written as,

⇒

x

360

−

(x+5)

360

=1

⇒

x(x+5)

x+5−x

=

360

1

⇒x

2

+5x=1800

⇒x

2

+5x−1800=0

⇒x

2

+45x−40x−1800=0

⇒x(x+45)−40(x+45)=0

⇒(x+45)(x−40)=0

⇒x=40,−45

But, speed can not be negative.

Hence, speed is 40 km/hr

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