A train travels 360 km at uniform speed. If the speed had been 10 km/hr, it would have taken 3 hour less for the same journey. What is the speed of the train?
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Answer:
Step-by-step explanation:
let the speed of train be x km/h
time taken = distance / speed= 360/x hr
second cond
increased speed = x+10 km/h
time taken = distance / speed= 360/x+10 hr
A.T.Q
360/x -360/x+10 = 3
360(1/x -1/x+10) = 3
360(10/x^2+10x)=3
3x^2+30x-3600=0
3(x^2 +10x - 1200)=0
x^2+10x-1200
now a=1 b= 2 c= -1200
D= b^2 - 4ac= (2)^2 - 4*1*-1200
4+4800=4804
x= 70.3 km/h
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