Question

A train travels 360 km with uniform speed if the speed of train is increased by 5 km per hour it take 48 minutes less to cover the same distance find the initial speed of the train?



please answer then u got 100 pt

Answer 1

Hey! ! !

Solution :-

☆ Let speed be x

:- T=360/x

●If speed is increased by 5 km/h

●speed will be (x+5)km/h

●distance is the same

:- T= 360/(x+5)

☆time with original speed - time with increased speed = 1

:- 360/x - 360/(x+5)=1

LCD= x(x+5)

(360(x+5)-360x) /x(x+5)=1

360x+1800-360x=x(x+5)

x^2+5x = 1800

x^2+5x-1800=0

x^2+45x-40x-1800=0

x(x+45)-40(x+45)=0

(x-40)(x+45)=0

x= 40 mph the original speed ,i;e speed of train is 40 mph

☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡

Answer 2

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Que) A train travels 360 km with uniform speed if the speed of train is increased by 5 km per hour it take 48 minutes less to cover the same distance find the initial speed of the train?

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Let original Speed = s
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Difference in time taken is 1 hour.
$<b><font face=copper black size=4 color=orange>$
=> 360/s - 360/(s + 5) = 1
$<b><font face=copper black size=4 color=blue>$
=> 360s + 1800 - 360s = s(s + 5)
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=> s(s+ 5) = 1800
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Since √1800 > 40 and √1800 < 45, both factors should be within this range and the difference must be 5, we have :
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40 x 45 = 1800.
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No other combination is possible.
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=> s = 40 kmph