Question

A train travels 360k.m at a uniform speed.the speed had been 5k.m/hr more ,it would have taken 1 hour less for the same journey.find the speed of the train.

Answer 1

Answer:

factorise that equation

MARK AS BRAINLIEST PLZZ

Answer 2

$\huge\underline\mathcal\purple{Solution}$

Let the speed of train be x

Total distance = 360km

according to question

$\large\frac{360}{x}-\large\frac{360}{x+5}={1}$

$\large\frac{360(x+5)-360x}{x(x+5)}={1}$

$\large\frac{360x-360x+1800}{x(x+5)}={1}$

$\large\frac{1800}{x^2+5x}={1}$

${1800}{=}{x^2+5x}$

${x^2+5x-1800}={0}$

${x^2+45x-40x-1800}={0}$

${x(x+45)-40(x+45)}={0}$

${(x-40)(x+45)=0}$

Either

x = 40km/h

or

x = -45km/h

But speed never in negative

so , speed of a train is 40km/h