Physics, asked by janetvarghese7337, 1 year ago

A train travels 40% faster than a car. Both start from point a at the same time and reach point b, 140 km away at the same time. On the way the train takes 25 minutes for stopping at the stations. What is the speed (in km/hr) of the train? Trick

Answers

Answered by GENIUS1223
1

Like these type of question, you have to equate with time.

So,the basic equation is:-

(Time taken by train without stopping) +

25/60= (time taken by car to go)

[25/60 hrs - stopping time]

[ In LHS, we are adding because, speed of train is greater than speed of car. So, time taken be train is lesser than car. ]

Let the speed of car be →x km/hr

Then, speed of train →40(x)/100 + x

=> 140x/100 ==> 7x/5 km/hr

We have been given that distance is 140km.

By using T= D/V formula…

#Time taken by train= 140/(7x/5) =

100/x hrs.

#Time taken by car= 140/x hrs.

So, substituting the value of these times in our equation. We get-together

100/x +25/60= 140/x

100/x - 140/x = -25/60

x = 96 km/hr.

Therefore,

Speed of train is 7x/5 = 7(96)/5

134.5 km/hr….

Hope this is helpful

Answered by seemasssingh4p893y4
2

Answer:

here is your answer

I hope it will help u

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