Question

A train travels a distance
of 300km at a uniform
speed. If the speed of the train increased by 5 km an
hour the sourney would
have taken 2 hours less.
Find
the original speed of
the train​

Answer 1

Answer:

25 km

Step-by-step explanation:

d=300

original speed =x

distance÷speed=time

300÷x=t

new speed(x+5)

300=300÷(x+5)

300÷x-300÷x+5=2

300(x+5)-300x÷x(x+5)=2

300x+1500-300x=2x^2+10x

2x^2+10x-1500=0

x^2+5x-750=0

x^2+30x-25x-750=0

x( x+30)-25(x+30)=0

(x+30)(x-25)=0

(x+30)=0, x==-30

(x -25)=0,x=25

so the original speed is 25km per hour