Question

A train travels a distance of 300km with constant speed. Speed of train incresed by 5km/hr the journey would take 2hrs less then original speed of train is ?

Answer 1

Answer:

Let the original speed of the train be y km / hr .

A.T.Q.

$\displaystyle{\frac{300}{y} -\frac{300}{y+5} =2 }$

300 ( y + 5 ) - 300 y = 2 y ( y + 5 )

y² + 5 y - 750 = 0

y² + 30 y - 25 y - 750 = 0

( y + 30 ( y -25 ) = 0

y = - 30 or y = 25

Since , speed of train can't be negative .

Therefore , the original speed of the train is 25 km / hr .