Question

A train travels a distance of 480 km as a uniform speed. If the speed had been
8 km/h less, then it would have taken 3 hours more to cover the same distance. Wie
need to find the speed of the train​

Answer 1

Step-by-step explanation:

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Answer 2

Let the initial uniform speed is x .

Let the initial uniform speed is x .time taken = 480/x

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8)

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160=> x²-8x = 1280

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160=> x²-8x = 1280=> x²-8x-1280=0

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160=> x²-8x = 1280=> x²-8x-1280=0=> x² -40x + 32x -1280 = 0

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160=> x²-8x = 1280=> x²-8x-1280=0=> x² -40x + 32x -1280 = 0=> x(x-40) + 32( x-40) = 0

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160=> x²-8x = 1280=> x²-8x-1280=0=> x² -40x + 32x -1280 = 0=> x(x-40) + 32( x-40) = 0 => (x-40) (x+32) = 0

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160=> x²-8x = 1280=> x²-8x-1280=0=> x² -40x + 32x -1280 = 0=> x(x-40) + 32( x-40) = 0 => (x-40) (x+32) = 0 therefore ,

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160=> x²-8x = 1280=> x²-8x-1280=0=> x² -40x + 32x -1280 = 0=> x(x-40) + 32( x-40) = 0 => (x-40) (x+32) = 0 therefore , => (x-40) = 0

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160=> x²-8x = 1280=> x²-8x-1280=0=> x² -40x + 32x -1280 = 0=> x(x-40) + 32( x-40) = 0 => (x-40) (x+32) = 0 therefore , => (x-40) = 0=> x = 40

Let the initial uniform speed is x .time taken = 480/x if speed is less than time taken = 480/ (x-8) A/Q => 480/(x-8) - 480/x = 3 => (x-x+8)/x(x-8) = 3/480=> 8/ x²-8x = 1/160=> x²-8x = 1280=> x²-8x-1280=0=> x² -40x + 32x -1280 = 0=> x(x-40) + 32( x-40) = 0 => (x-40) (x+32) = 0 therefore , => (x-40) = 0=> x = 40so , speed of train = 40 km/h