A train travels a distance of 480 km at a uniform speed. If the speed had
been 8 km/hr less, then it would have taken 3 hours more to cover the
same distance. Find the usual speed of the train.
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Step-by-step explanation:let the usual speed be x km/h
then, 480/x-480/x-8 =3
480(1/x-8-1/x)=3
x-(x-8)x²-8x=160
+8(160)=x²-8x
x²-8x-1280=0
x²-40x+32x-1289=0
x(x-40)+32(x-40)=0
(x+32)(x-40)=0
x= -32;+40
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