Math, asked by singhmk15071981, 8 months ago


A train travels a distance of 480 km at a uniform speed. If the speed had been
need to find the speed of the train.
8 km/h less, then it would have taken 3 hours more to cover the same distance. We​

Answers

Answered by rudraBajaj21
3

Answer:

the speed had been 8 km/h less, then it would have taken 3 hours more to cover the same distance. We need to find the speed of the train. But speed of the train cannot be –ve. x = 40.

Answered by MaIeficent
33

Step-by-step explanation:

Correct Question:-

A train travels a distance of 480km at a uniform speed. If the speed had been 8km/h less, then it would have taken 3 hours more to cover the same distance. We need to find the speed of the train.

\bf{\underline{\underline\red{Given:-}}}

  • Distance = 480km

  • If speed is decreased by 8km/h, it would take 3hours more to cover the same distance.

\bf{\underline{\underline\blue{To\:Find:-}}}

  • The speed of the train.

\bf{\underline{\underline\green{Solution:-}}}

Given, Distance = 480km

Let the speed be x km/h

\boxed{ \rm \leadsto Time =  \frac{Distance}{Speed} }

{ \rm \implies Time =  \dfrac{480}{x} \: hrs }

\rm If\: speed\: is \:decreased \:by \:8km/h

\rm Speed = (x-8)km/hr

\rm As\: distance\: is \:same

\rm Distance = 480km

\rm Time = \dfrac{480}{x-8}

Given, if speed is decreased by 8km/h, time taken is 3 hours more

{ \rm \implies  \dfrac{480}{x -  8}    = \dfrac{480}{x} + 3  }

{ \rm \implies  \dfrac{480}{x -  8}     - \dfrac{480}{x}  = 3  }

{ \rm \implies  \dfrac{480(x) - 480(x - 8)}{x(x -  8)}      = 3  }

{ \rm \implies  \dfrac{480x - 480x  + 3840}{ {x}^{2}  -  8x}      = 3  }

{ \rm \implies  { 3840}    = 3 ( {x}^{2}   - 8x)}

{ \rm \implies  \dfrac { 3840} {3}   =  {x}^{2}   - 8x}

{ \rm \implies 1280  =  {x}^{2}   - 8x}

{ \rm \implies  {x}^{2}   - 8x - 1280 = 0}

{ \rm \implies  {x}^{2}   - 40x  + 32x -  1280 = 0}

{ \rm \implies  {x}(x - 40) + 32(x -  40) = 0}

{ \rm \implies  (x - 40)(x  + 32) = 0}

{ \rm \implies  x - 40 = 0 \:  \:  \: (or )\:  \:  \: x  + 32= 0}

{ \rm \implies  x  = 40 \: , \:  - 32}

Since, speed of the train cannot be negative

{ \rm \implies  x  = 40 }

 \underline {\boxed{ \rm  \purple{ \therefore Speed \: of \: the \: train  = 40km/h}}}

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