A train travels a distance of 480 km at a uniform speed. If the speed had been
8 km/h less, then it would have taken 3 hours more to cover the same distance. We
need to find the speed of the train.
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Here,
d= 480km
s/t= 480
s= 480/t (1)
Now,
New Speed = speed-8
New time= t+3
So, covering the same distance
will be given by,
D= s×t
480= (s-8)(t+3)
480= (480/t -8)(t+3)
480= (480-8t)/t ×(t+3)
480t= 480t+1440-8t²-24t
0= -8t²-24t+1440
8(t²+3t-180)=0
t²+3t-180=0
t²+15t-12t-180=0
t(t+15)-12(t+15)=0
(t-12)(t+15)= 0
either t= 12
or t= -15
Since time cannot be negative, t= 12 hr
plugging the value of t in equation (1)
s= 480km/12h
= 40km/hr
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