Question

A train travels at 20m/s acclerates at 0.5 m/s square for 30 seconds How far it trwvel in this time​

Answer 1

Answer:

825 m

Explanation:

As per the provided information in the given question, we have:

• Initial velocity (u) = 20 m/s
• Acceleration (a) = 0.5 m/s²
• Time taken (t) = 30 seconds

We have to calculate the distance covered in this time.

By using the second equation of motion,

$\longrightarrow \sf{\quad {s = ut + \dfrac{1}{2}at^2 }}$

• s denotes distance
• u denotes initial velocity
• t denotes time
• a denotes acceleration

$\longrightarrow \sf{\quad {s = 20(30) + \dfrac{1}{2}\times 0.5 \times (30)^2 }}$

$\longrightarrow \sf{\quad {s = 600 + \dfrac{1}{2}\times 0.5 \times 900 }}$

$\longrightarrow \sf{\quad {s = 600 + 1 \times 0.5 \times 450 }}$

$\longrightarrow \sf{\quad {s = 600 + 225 }}$

$\longrightarrow \quad \underline{\boxed{\pmb{\frak{s = 825 \; m}} }}$

Therefore, it travelled 825 m in this time.

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Learn More :

Equations of motion :

$\boxed{ \begin{array}{cc} \pmb{\sf{ \quad \: v = u + at \quad}} \\ \\ \pmb{\sf{ \quad \: s= ut + \cfrac{1}{2}a{t}^{2} \quad \: } } \\ \\ \pmb{\sf{ \quad \: {v}^{2} - {u}^{2} = 2as \quad \:}}\end{array}}$

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time
• s denotes distance