A train travels at a certain average speed for a distance of 54 km and then travels a distance of 63 km at an average speed of 6 km/h more than the first speed. If it takes 3 hours to complete the total journey, what is its first speed?
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Total distance travelled= (54+63)km= 117 km
Total time taken= 3 hrs
Let the average speed for the first 54 km be x km/h
And the average speed for second 63 km be (x+6) km/h
Total distance travelled= x+(x+6) km in 3 hrs
= 2x+6 km/h, which is equal to the total speed of the train.
Speed= Distance/Time,
(2x+6) km/h= (117 km)/(3 hrs)
6x+18= 117
x= 16.5
(x+6)= 16.5+6= 22.5
First average speed of the train= 16.5 km/h
HOPE IT HELPS.
Total time taken= 3 hrs
Let the average speed for the first 54 km be x km/h
And the average speed for second 63 km be (x+6) km/h
Total distance travelled= x+(x+6) km in 3 hrs
= 2x+6 km/h, which is equal to the total speed of the train.
Speed= Distance/Time,
(2x+6) km/h= (117 km)/(3 hrs)
6x+18= 117
x= 16.5
(x+6)= 16.5+6= 22.5
First average speed of the train= 16.5 km/h
HOPE IT HELPS.
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