A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72km at an average speed of 6km/hr more than its onginal speed. If it takes 3 hours to complete the total journey, what is its original speed?
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Let original speed of the train be x km/h.
Then, time taken to travel 63 km = 63/x hours
New speed = (x + 6) km/hr
Time taken to travel 72 km = 72/(x + 6) hours
According to the question,
63 72 + X x+6 = 3 = 63x +378 +72x x² + 6x = 3
135x + 378 = 3x² + 18x 3x²-117x-378= 0
x²-39x - 126 = 0
(x-42)(x + 3) = 0
x = -3 or x = 42
As the speed cannot be negative, x = 42
Thus, the average speed of the train is 42 km/hr.
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