A train travels at a certain average speed for a distance of 54 km and then travels a distance of 63 km at an average speed of 6km/h more than the first speed in 3 hours then find the speed
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speed during 63 km/h is given as
= 63km/(3hours)
= 21 km/h
now speed during first journey
= 21 km/h- 6km/h
= 15 km/h
I hope it helps you.
thanks for asking.
please rate it as brainliest.
= 63km/(3hours)
= 21 km/h
now speed during first journey
= 21 km/h- 6km/h
= 15 km/h
I hope it helps you.
thanks for asking.
please rate it as brainliest.
varun6973:
it is right or wrong answer
correct answer.
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