A train travels at a certain average speed of 54 km and then travels a distance of 63 km at an average speed of 6km/h more than its average speed. If it takes 3 hours to complete the journey, what is its original average speed?
Answers
Answered by
6
Answer:
36km/hr is the speed
Step-by-step explanation:
Solution :
Distance =54km
Let the average speed be x
Distance =63 km
The average speed to cover this distance =x+6
Total time taken =3hr
DS=t
∴54x+63x+6=3
54(x+6)+63xx(x+6)=3
54x+324+63x=3x2+18x
=> 3x2−99x−324=0
=> x2−33x−108=0
(x−36)(x+3)=0
x=36 or −3
x=−3 is not admissible
Hence x=36km/hr is the speed
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Answered by
3
Answer:
Let the average speed of the train be x km/hr
Distance travelled by train =54 km
D=S x t
54=(x) t
T=54/x............(1)
Distance travelled by train =63km
New speed= (6+x)
D= S x T
63 = (6+x) t
T= 63/6+x.............(2)
According to question:-
54/x + 63/x+6=3
54x + 324 + 63x/ x^2 + 6x =3
54x+324+63x = 3x^2 +18x
3x^2 - 99x -324=0
Now solve it by middle term splitting
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