a train travels at a certain average speed of distance of 54 km and then travels a distance of 63 km at an average speed of 6 km/hr more than its original speed.if it take 3 hours to com[let the total journey , what is the original average speed ]
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we know that distance = speed * time.
let the original speed be x
ATQ
54/x+63/x+6=3
x2-33x-108= 0
(x-36)(x+3)..
, therefore the original speed is 36 km/ hr
priya5485:
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