Question

a train travels certain average speed for a distance of 80 km and then travels a distance of 24 km at an average speed of 5km/hr more than its original speed. if it takes 4 hrs. more to complete the total journey, what is its original speed???

Answer 1

original time is 80/x
where x is speed
according to the question
original time+4=new time
80/x +4=24/(x+5)
80/x=24/(x+5) -4
80/x=(24-20-4x)/(x+5)
80/x=(4-4x)/(x+5)
80(x+5)=(4-4x)x
80x+400=4x-4x2
4x2+76x+400=0
x2+19x+100=0
The equation coming has imaginary roots

Answer 2

hey mate
this is not possible because this equation doesn't have equal roots