Question

A train travels for 30 min with a velocity of 60 Km/h and then for 40 min with a velocity 30 Km/h in the

same direction, Calculate [4]

(1) The total distance travelled

(2)The average velocity of the train​

Answer 1

Answer:

Solution,

here,

CASE (i)

when time travel (t1) = 30 min

=30/60h =1/2h velocity (v1) = 60km/h

we know

distance = velocity × time

d1 = v1×t1 = 60×1/2 = 30m

CASE (ii)

when time (t2) = 40 min

= 40/60h =2/3h

velocity (v2) = 30km/h

d2 = v2×d2 = 30×2/3 = 20m

So, the total distance travelled = d1+d2

= 30+20

= 50m

Also,

Average velocity of the train = v1+v2/2

= 60+30/2

= 45km/h

I HOPE IT HELPS YOU!!!

Answer 2

Answer:

The total distance is 41.6 km and the average velocity is 35 km/h

Explanation:

Given that,

Time in first travel = 30 min

Velocity of first travel = 30 km/h

Time in second travel = 40 min

Velocity of second travel= 40 km/h

The distance covers in first travel

d = v×t

d = 30×1/2

d = 15 km

The distance covers in second travel

d = v×t

d = 40×2/3

d = 26.6 km

The total distance is

D = d¹+d²

D = 15+26.6

D = 41.6 km

The average velocity is

Vav = (V²+V¹)/2

Vav = (40+36)/2

Vav = 35 km/h

Hence, The total distance is 41.6 km and the average velocity is 35 km/h.