Question

a train travels from a station A to the station B in 60min.it halts in the station B for 10 min and returns to the station A in 50min. Given the distance between the stations A and B is 80km.calculate the average speed of the total journey ​

Answer 1

Answer:

average speed of 1st Journey = 8/6= 1.3min/km

average speed of return journey =8/5= 1.6min/km

average speed = 160/110=1.45454min/km

Answer 2

Answer:

The average speed of total journey is 80km/h

Explanation:

Given that,

A train travels from a station A to the station B in 60min and it halts in the station B for 10 min and returns to the station A in 50min.

Also given that,

The distance between the stations A and B is 80km.

We are required to find the average speed of entire journey which is the ratio of total distance to total time taken during journey.

$V_{avg}=\frac{Total\:distance}{Total\:time}$

Total distance is

$d=d_{AB}+d_{BA}=80km+80km=160km$

Since we are finding average speed of journey,the halt time must also be considered.Therefore,

Total time is

$t=60min+10min+50min\\=120min=2hrs$

Hence the average speed of journey is calculated as

$V_{avg}=\frac{160km}{2hrs}=80km/h$

Therefore,

The average speed of total journey is 80km/h

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