Question

A train travels from A to B, a distance of 100 km.
at a speed of 20 km/h. If it had gone two and a
half times as fast, how much earlier would it have
arrived at B?

Answer 1

Answer:

here' your answer

3 hours earlier

Step-by-step explanation:

s = d/t

t = d/s

original time:

t = 100/20

t = 5 hours

at 2.5 times speed:

t = 100/(20*2.5)

t = 2 hours

answer:

it would arrive 3 hours earlier

hope it' will help you

Answer 2

Speed of the train = 20 km/h

New speed = 2.5 times the old speed

= 20 × 2.5=50km/h

Distance from A to B =100km

Speed =50km/h

The train reaches B after

100÷50=2hours

Earlier it was reaching after

100÷20=5hours

The train reaches 3 hours earlier.