Question

a train travels half of its journey with speed 30m/s and other half with the speed of 40m/s. calculate its average speed.​

Answer 1

Answer:

Let the total distance it covers be 2x.

Time taken to cover its first half of distance t1 :-

=> x/30

Time taken to cover its next half of distance t2 :-

=> x/40

Total time taken :- t1 + t2

=> x/30 + x/40

=> 7x/120

Average speed :- total distance / total time taken

=> 2x / (7x/120)

$= \frac{240}{ {7ms}^{ - 1} }$

$= > 34.3ms$

So the average speed is 35m/s.

Hope it helped ✌️ ✌️

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Answer 2

Answer:

The average speed is 34.28 m/s.

Step-by-step explanation:

Solution :

Half journey = 30 m/s

Other half = 40 m/s

★ Average Speed = Total Distance/Total Time

Distance = 30 m/s and distance travelled at 40 m/s (same distance was travelled)

Time = Distance/Speed

• At 30 m/s = d/30
• At 40 m/s = d/40

Total Time = d/30 + d/40

= 4d/120 + 3d/120

= 7d/120

Average Speed = (d + d)/(7d/120)

= 240/7

= 34.28 m/s

Therefore, the average speed is 34.28 m/s.