Question

A train travels some distance with a speed of 45km/h and returns with a speed of 30km/h . Calculate the average speed of the train.

Answer 1

Answer:

36 kmph

Explanation:

Let V1 = 30 kmph

and V2 = 45 kmph

Since distance is equal, we can use,

$vavg = \frac{2v1v2}{v1 + v2} \\ = \frac{2 \times 30 \times 45}{30 + 45} \\ \frac{2 \times 30 \times 45}{75} \\ \frac{180}{5} \\ = 36 \: kmph$

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