a train travels the first 30 km of 120 km track with a uniform speed of 30km/h.what should be the speed of train to cover the remaining distance of the track so that its average speed is 60 km/h for the entire trip.
Answers
Answered by
6
track =120
30km =30km/h
120-30=90km
90km=60km/h
So. 90/60
=. 3/2 that is 1 hours and 30min
30km =30km/h
120-30=90km
90km=60km/h
So. 90/60
=. 3/2 that is 1 hours and 30min
Answered by
2
ANSWER
In the first 30 km speed of the train, v1 = 30 km/h
Speed of the train in the next 90 km, v2 (to be determined)
Average speed = 60 km/h = (v1 + v2)/2
= (30 km/h + v2)/2
→ v2 = 90 km/h
Similar questions