A train trevels a distance of 360km at a uniform speed.If the speed of the train is 5km more per hour,then it could have taken one hour less for the same journey,find the speed of the train?
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Step-by-step explanation:let the speed be x km/h
D=360km
T1=360/x
Speed2=(x+5)km/h
T2=360/x+5
Acc. To question
T1-t2=1
360/x-360/x+5=1
360(x+5-x)/x^2+5x=1
360×5=x^2+5x
X^2+5x-1800=0
X^2+45x-40x-1800=0
X(x+45)-40(x+45)=0
X=40km/h
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