A train was late by 6 min. the driver increased its speed by 4 km/hr. at the next station, 36 km away, the train reached on time. find the original speed of the train??
Answers
Hope this will help
Original Speed of Train = 36 km/Hr
Step-by-step explanation:
A train was late by 6 min. the driver increased its speed by 4 km/hr.
Let say Original Speed of Train = T km/hr
next station, 36 km away
in Next 36 km train was supposed to take time = 36/T hr
Increased Speed = T + 4 km/hr
Time taken = 36/(T + 4) hr
the train reached on time => Train saved 6 mins by increasing speed
6 mins = 6/60 = 1/10 hrs
=> 36/T - 36/(T + 4) = 1/10
=> 360 (T + 4) - 360T = T(T + 4)
=> 1440 = T² + 4T
=> T² + 4T - 1440 = 0
=> T² + 40T - 36T - 1440 = 0
=> T(T + 40) - 36(T + 40) = 0
=>(T - 36)(T + 40) =0
=> T = 36
Original Speed of Train = 36 km/Hr
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