Question

A train was moving at the rate of 54km h when brakes were applied.It came to rest within a distance of 225m.Calculate produced in the train

Answer 1

Answer:

formula is v^2-u^2=2as

Explanation:

inital velocity u=54 km/h

final velocity v=0 km/h

s=225m or 0.22 km

-(54)^2=2(0.22)a

a=-2916/0.44

a= -6627.27 m/s^2

retardation produced is 6627.27 m/s^2

hope this helps