Question

A train was moving with a velocity of 30m/s.After applying brakes the velocity is reduced to 10m/s in 240 m . When the velocity of train is zero, what is the distance ?
Please help me!!!

Answer 1

HEYA MATE,

HERE IS UR ANSWER.

Thanks for asking this question.

Given

U-30 m/s
V-10 m/s
S-230m—————————-——-—-3️⃣
From v2−u2=2as

102−302=2∗a∗240

-800=480 x a

a= -800/480 - - - - - ———————-- - 1️⃣

Now,when the trains velocity is 10…

U-10 m/s
V-0 m/s
A= - 800/480 (using 1)
Using the same EQUATION

0 - 102= 2 x a x s

-100 =-1600/480 x s

S=-100 x - 480/1600

S=30m - - - - - - - - - - - - - - - - - - - - - - - 2️⃣

This is the distance for 2nd part of travel

So the total d is (3)+(2)

=240m +30m = 2️⃣7️⃣0️⃣ meters ✌️✌️

I HOPE IT HELPS U.

Answer 2

U = 30m/s
v=10m/ s
d=240m
using 3rd equation of motion i.e v2 = u2 +2as
100=900+480a
-800=480a
-5/3 = acc
now....
when v=0
acc=-5/3
U =30m/s

again,by using 3rd equation of motion
0=900-5/3×s
5/3s=900
180×3=s
540m =s 《 answer

**hope this answer helps **