Question

A train, which is moving with the velocity of 108 km/hr is brought to rest in 3 minutes on applying the brakes. Find
(a) the retardation and
(b) the distance that the train travels before coming to rest.

Answer 1

Answer:

Given,

u=108km/h=

60×60

108×1000

=30m/s

a=−1m/s

2

v=0m/s

From 3rd equation of motion,

2as=v

2

−u

2

−2×1×s=0

2

−30×30

s=

−2×1

−30×30

s=450m