Question

A train with a speed of 54kmph.The driver applies brakes so that a uniform retardation of 0.4m/s^2 is produced. The distance travelled by the train before it comes to rest is __________. Options 1)280.2m 2)281.25m 3)283.2m 4)284.2m

Answer 1

Answer:

Explanation:

speed of train = 54 km/hr

                        = 15 m/s

acceleration = $_$-0.4 m/s       (negative sign because retardation)

the final velocity is 0 as the train comes to stop

So, from the third equation of motion

v²- u²=2×a×S   where s is the distance traveled by the train before coming to stop

S=(v²- u²)/2a

 v=0

S=(-u²)/2a

S=(-(15)²)/2× -0.4

S=281.25m

hope this helps

pls mark brainliest