A train with a uniform speed, crosses a platform, 162 metres long, in 18 seconds and another platform, 120 metres long, in 15 seconds. the speed of the train is
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Answered by
0
Average speed= 2V1.V2/V1+V2
Our 1st objective is to find V1
V1=162/18
V1=9m/s
now,V2
V2=120/15
V2=8m/s
putting the values in the formula of avg speed(u):-
u=2(9)(8)/9+8
u=144/17
u=8.47m/s
Our 1st objective is to find V1
V1=162/18
V1=9m/s
now,V2
V2=120/15
V2=8m/s
putting the values in the formula of avg speed(u):-
u=2(9)(8)/9+8
u=144/17
u=8.47m/s
Answered by
4
distance by train = 162 - 120
= 42 metres
time taken by train = 18-15
=3 seconds
speed = d/t
= 42/3
=14m/s
= 42 metres
time taken by train = 18-15
=3 seconds
speed = d/t
= 42/3
=14m/s
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