A train with mass 40000 kg moving with a velocity of 60 m\ s comes at rest in 10 sec by applying the brakes. What is the retardation of a train and force on the brake?
Answers
Answered by
1
Explanation:
mass = 40000kg
initial v. = 60m/s
final v. = 0m/s
time = 10sec
F = ma
a =??
v = u + at ----(1 eq)
0 = 60 + (a)10
-60/10 = a
a = -6 m/s² ------ retardation
F = (40000)(-6)
= -24000N ------- force applied to stop
Answered by
35
↬ Given :-
- Mass (m) = 40000 kg
- Initial velocity (u) = 60 m/s
- Time (t) = 10 sec
- Final velocity (v) = 0 m/s
↬To find :-
- Retardation of the train = ?
- Force on the break = ?
↬ Solution :-
Hence,the retardation of the train will be -6 m/s².
Now,
we know that,
Hence,the force on the break will be -240000 N.
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