A traingle having median 9,40,41 respectively, find the area of triangle?
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Hi, Vinod Bro,
Side = (a+b+c)/2
= (9+ 40+41)/2
= 90/2
=45cm
Area of the triangle = 4/9 √s(s-a)(s-b)(s-c)
= 4/9 √45(45-9)(45-40)(45-41)
= 4/9 √45×(36×5×4)
= 4/9 √45×720
= 4/9 √32400
= 4/9 × 180
= 80
If it not works instead of 4/9 use 4/3.
I hope this will help you
Side = (a+b+c)/2
= (9+ 40+41)/2
= 90/2
=45cm
Area of the triangle = 4/9 √s(s-a)(s-b)(s-c)
= 4/9 √45(45-9)(45-40)(45-41)
= 4/9 √45×(36×5×4)
= 4/9 √45×720
= 4/9 √32400
= 4/9 × 180
= 80
If it not works instead of 4/9 use 4/3.
I hope this will help you
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