A trangle ABC is right angled at B.Find the value of (secA.sinC-tanA.tanC)÷sinB
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Answer:
zero(0)
Step-by-step explanation:
secA×sinC-tanA×tanC÷sinB
h/p×p/h - b/p×p/b ÷ sinB
1-1÷ sinB
0÷sinB
0
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