Question

A transformer has 200 primary turns and 150 secondary
turns. If the operating voltage for the load connected to the
secondary is measured to be 300V, what is the voltage
supplied to the primary coil?​

Answer 1

Answer:

Voltage supplied to primary coil, V(p) = 400 V

Explanation:

number of turns in primary coil , N(p) = 200

number of turns in secondary coil,N(s) = 150

Voltage of the load connected to secondary , V(s) = 300 V

Voltage supplied to primary coil, V(p) = ?

we know,

in a transformer,

$\frac{N(s)}{N(p)} =\frac{V(s)}{V(p)} \\\\=> \frac{150}{200} =\frac{300}{V(p)} \\\\=> \frac{3}{4} =\frac{300}{V(p)} \\\\=> V(p)=300 (\frac{4}{3} )\\\\=> V(p) = 400 V$

⇒Voltage supplied to primary coil, V(p) = 400 V

Answer 2

Answer:

Voltage supplied to primary coil, V(p) = 400 V

Explanation:

number of turns in primary coil , N(p) = 200

number of turns in secondary coil,N(s) = 150

Voltage of the load connected to secondary , V(s) = 300 V

Voltage supplied to primary coil, V(p) = ?

we know,

in a transformer,

\begin{gathered}\frac{N(s)}{N(p)} =\frac{V(s)}{V(p)} \\\\= > \frac{150}{200} =\frac{300}{V(p)} \\\\= > \frac{3}{4} =\frac{300}{V(p)} \\\\= > V(p)=300 (\frac{4}{3} )\\\\= > V(p) = 400 V\end{gathered}

N(p)

N(s)

=

V(p)

V(s)

=>

200

150

=

V(p)

300

=>

4

3

=

V(p)

300

=>V(p)=300(

3

4

)

=>V(p)=400V

⇒Voltage supplied to primary coil, V(p) = 400 V