A transformer has 500 turns in the primary windings and 100 turns in the secondary side. The resistances in the primary and secondary sides are 0.3 and 0.1 respectively and the reactances are 2.0 and 0.1 respectively.
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Answer:
In usual rotation we have -
⇒VpVs=NpNs
∴VS=Vp×NpNs
=200v×5001000
=400V
There is load resistance of 100Ω in the secondary circuit. Therefore current in the secondary
⇒is=RsVs=100Ω400V=4A
In an ideal transformer the output power and input power are equal that is
⇒Vs×is=Vp×ip
∴ip=is×VpVs=4A×200V400V
=4A×2
=8A
Hence, the answer is 8A.
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