Question

A transformer has a primary coil with 1600 turns and a secondary coil with 1200 turns. If the current in the primary coil is 6 Ampere, then what is the current in the secondary coil of a transformer

Answer 1

Answer:

Secondary terminal

The given transformer is a step down transformer as the number of turns in the secondary is less than primary. So, the voltage gets reduced.

Given,

Number of turns in the primary, N1 = 1200

Number of turns in the secondary, N2 = 120

primary voltage, V1 = 240V

We have,

N2N1=V2V1

Where,

N1 is the number of turns in the primary winding

N2 is the number of turns in the secondary winding

V1 is the voltage across the primary winding

V2 is the voltage across the secondary winding

Substituting the given values in the equation we get,

1201200=V2240

1200V2=28800

V2=120028800=24V

So the lamps will connect as secondary side as the secondary voltage is 24V only.