A transformer steps down 220V to 44V. If the number of turns in the primary coil is 60 turns, what is the number of turns in the secondary coil?
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Answer:
The number of turns in the secondary coil is 12.
Explanation:
Voltage in the primary coil of the transformer, V₁ = 220 V
Voltage in the secondary coil of the transformer, V₂ = 44 V
Number of turns in the primary coil of the transformer, N₁ = 60
Let the number of turns in the secondary coil of the transformer be N₂.
The transformer equation is given by,
V₁/V₂ = N₁/N₂
⇒ N₂ = (V₂/V₁) × N₁
N₂ = (44/220) × 60
N₂ = 12
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