Question

A transformer with a power efficiency of 80% converts a 10 V primary input voltage (with a current of 10 A) to a voltage of 20 V. The current in the secondary coil will be O 15 A O 4 A O ZA o 10A​

Answer 1

you gave the answer dude

Answer 2

Given:

the efficiency of a  transformer η = 80%

input voltage Vi= 10 V

input current I$_i$ = 10 A

output voltage Vo =20V

To find:

The current in the secondary coil Io =?

Step-to-step-explanation:

• The efficiency of the transformer is defined as the intensity or the amount of power loss within a transformer.
• So the efficiency of the transformer is also defined as the ratio of output power to the input power which is equal to the ratio of the product of output current & output voltage to the product of input current & input voltage.

        $\displaystyle \eta = \frac{V_o\ I_o}{V_i\ I_i}$          ...(1)

         where

         Vo = output voltage

         Io = output current

         Vi = input voltage

         I$_i$ = input current

         $\displaystyle \frac{80}{100} = \frac{20\ I_o}{10\ 10}$

        Io = 4 A

Hence, the current in the secondary coil will be 4A.